Loop for words vector

2 vues (au cours des 30 derniers jours)
Dmytro
Dmytro le 30 Mai 2014
Commenté : Yusef Ghazwan le 16 Juin 2020
Hallo everyone. I have a question. Is it possible to use a loop to create vector of words depending on the number.
As input I have a number, which can be changed according to any wish. And as a result i wont to get a row of words %input Number=10
C = cell(1,Number)
for i=1:Number
C(1,i)={'portfolio' *i* };
end
And using the loop I want a change of index "i"
Asa result Output have to be something like that: C={'portfolio 1','portfolio 2','portfolio 3','portfolio 4',......'portfolio 10'};
Hope to hear from you soon. Thanks in advance!
  1 commentaire
Yusef Ghazwan
Yusef Ghazwan le 16 Juin 2020
Show the output!

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Geoff Hayes
Geoff Hayes le 30 Mai 2014
You can use the sprintf command to do what you require. Just modify your body of the for loop from what you have to
C{i} = sprintf('portfolio %d',i);
Note that since your code has defined C to be a cell array, the curly braces {} are used to access elements within it.
  1 commentaire
Dmytro
Dmytro le 30 Mai 2014
It is alive!!!! Thank you a lot!!!

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