my matrix is not square, although i think it is?
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I have set the following least squares method up quickly. I know i am using a nonlinear technique to solve a linear problem, however i just wanted to get it working, before i choose a linear method but aparently my matrices are not square:
i = [1 2 3 4 5];
ti = [2 5 7 11 14];
Estimates3=fminsearch(@functionnumbers,1,options,T0,theta_f);
and the function code
function fnumbers = functionnumbers(params3,i,ti)
k = params3;
v0 = 1 + (k/2)*ti(1)^2/ti(1)
fnumbers = sum(ti.^2*(i/ti-(v0-(k/2)*ti))^2);
cheers
3 commentaires
Réponse acceptée
Walter Roberson
le 8 Août 2011
fminsearch() accepts at most 3 inputs, and the function passed to it must accept a single input. See http://www.mathworks.com/help/techdoc/ref/fminsearch.html
5 commentaires
Walter Roberson
le 9 Août 2011
Are you truly wanting to do a _matrix division_ between i and ti ?? If not then you should be using ./ instead of /
Are you truly wanting to do a matrix multiplication between ti.^2 and the rest of the expression? If not, then you should be using .* instead of *
Plus de réponses (1)
Alex
le 9 Août 2011
2 commentaires
Walter Roberson
le 9 Août 2011
In the original equation you had "i" divided by "ti", but in the new equations that division appears to have vanished. It does not appear to me that your old and new equations are equivalent, but it could be that I missed something.
Voir également
Catégories
En savoir plus sur Get Started with Optimization Toolbox dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!