how shall i keep the particular position of a column of a matrix to to repeat for all other columns?????
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suchismita
le 18 Juin 2014
Commenté : suchismita
le 18 Juin 2014
this is a code ::::
a1=rand(10,10);
a=a1(:,1);
a=a';
c=ceil(a); %% when err=1 err=1;
maxValueRowWise=max(a');
for k=1:length(maxValueRowWise)
c(a==maxValueRowWise(k))=0;
end
% disp('For err=1')
% c
%%when err=2
err=2;
s=sort(a,2);
twoMaxValueRowWise=s(:,end-1:end);
for k=1:numel(twoMaxValueRowWise)
c(a==twoMaxValueRowWise(k))=0;
end
% disp('For err=2')
% c
%%when err=3
err=3;
s=sort(a,2);
ThreeMaxValueRowWise=s(:,end-2:end);
for k=1:numel(ThreeMaxValueRowWise)
c(a==ThreeMaxValueRowWise(k))=0;
end
% disp('For err=3')
% c
%%when err=4
err=4;
s=sort(a,2);
ThreeMaxValueRowWise=s(:,end-3:end);
for k=1:numel(ThreeMaxValueRowWise)
c(a==ThreeMaxValueRowWise(k))=0;
end
disp('For err=')
c
[y]=find(c==0)
here y indicates the position of error now in a1 the y row element every node will give wrong answer if by round(a1) is 1 than 0 else 1.
this whole process will be running for 10 times and in every iteration this y wont change and it will give error. plz plz plz help me out....
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