Convert string of hex to array of dec

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John Ramshur
John Ramshur le 17 Août 2011
I need to convert a string of hexidecimal numbers to an array of dec numbers. The string can potentially contain incomplete hex numbers at the beginning and end of the string. See examples below. I'm trying to use this in a data acquisition setup...so execution time could be a factor.
Input String Examples ('/r' = carriage returns:
s1 = '0001h/r0002h/r0003h/r';
s2 = '4h/r0001h/r0002h/r0003h/r00';
Output Desired:
a1 = [1,2,3]
a2 = [1,2,3]

Réponse acceptée

Fangjun Jiang
Fangjun Jiang le 17 Août 2011
s1 = '0001h/r0002h/r0003h/r';
s1 = '4h/r0001h/r0002h/r0003h/r00';
str=regexp(s1,'h/r','split');
Ind=cellfun(@length,str);
str=str(Ind==4);
num=hex2dec(str);
  2 commentaires
John Ramshur
John Ramshur le 17 Août 2011
Worked perfectly. Thanks.
Jan
Jan le 17 Août 2011
cellfun('prodofsize', str) is faster than cellfun(@length, str).

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Plus de réponses (1)

Jan
Jan le 17 Août 2011
A simpler method, which is substantially faster:
s1 = '0001h/r0002h/r0003h/r';
a1 = sscanf(a, '%xh/r')
But this does not reject the 4 of the string '4h/r0001h/r0002h/r0003h/r00'!
If you mean \r instead /r:
s1 = sprintf('0001h\r0002h\r0003h\r');
a1 = sscanf(a, '%xh')

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