difference between normcdf and 1-erfc

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the cyclist
the cyclist le 6 Juil 2014
No. Here is some simple code that creates a plot that illustrates that those two functions are not equal:
x = -5 : 0.01 : 5;
y1 = normcdf(x);
y2 = 1-erfc(x);
figure
plot(x,y1,x,y2)
legend('normcdf','1-erfc')

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Tri
Tri le 6 Juil 2014

0 votes

Thank you! After further research, looks like normcdf = 0.5*erfc(-x/(sqrt(2))

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