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Simple Question ( for loop with differnt variables)

2 vues (au cours des 30 derniers jours)
Max Müller
Max Müller le 15 Juil 2014
Commenté : Max Müller le 15 Juil 2014
Heyho folks,
This is a really simple example for the Question I have.
for i=1:3
eval ( ['A' num2str(i) '=i'] )
end
generates A1 = 1 / A2 = 2 /A3 = 3
now i want to use these variables.....but how?
for i= 1:3
B = A{i} + 1
end %nope doesnt work
for i =1:3
B = ([A num2str(i)]) +1
end %nope doesnt work
............

Réponse acceptée

Azzi Abdelmalek
Azzi Abdelmalek le 15 Juil 2014
Modifié(e) : Azzi Abdelmalek le 15 Juil 2014
Why are you complicating things?
for i=1:3
A(i)=i
end
for i= 1:3
B(i) = A(i) + 1
end
  4 commentaires
Yoav Livneh
Yoav Livneh le 15 Juil 2014
If you want to use A1, A2, etc. you will have to continue using eval. I recommend switching to an array or cell array, or even a structure, in order to better access your data.
Max Müller
Max Müller le 15 Juil 2014
Thanks, Guys...it worked....guess i am going to sleep now.....

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