Frequency Magnitude histogram plot

Hi I have two variabes (Freq and magnitude) I want to plot the histogram so that I get Freq on y axis and magnitude on x-axis.

Please guide

[Wayne King]

Can you please attach your data or a picture of what you're trying to get. It's not clear from your question what you want.

[Daniel kiracofe]

so, by definition, a "histogram" has counts on the y-axis. i.e. you can only plot a histogram of 1 variable, not 2. Unless I had misunderstood the question.

[amberly hadden]

Data                  Frequency
2.10-2.199    43
2.2-2.299    41
2.3-2.399    31
2.4-2.499    29
2.5-2.599    13
2.6-2.699    9
2.7-2.799    3
2.8-2.899    2
2.9-2.999    1

[Star Strider]

Relevant history: hi, I want to split my data set into different series lets say its from 2.0 to 2.99 I want to make intervals like 2.00 - 2.199, 2.2-2299, 2.3-2.3999 and then would like to to count the number of values for each interval..

Answer 1

[Kelly Kearney]

Is this what you had in mind?

xedge = 2.1:.1:3;
freq = [43 41 31 29 13 9 3 2 1];

bar(xedge, [freq 0], 'histc')

[Image Analyst]

jay's "Answer" moved here since it's not an answer to the original question:

Nope I need binning of data and then to creat a histograme which would be exaclty same as figure I have attached above.

Thank you

[Image Analyst]

Well, you have not given your original data. The data you gave is already the "counts" - just as if you have already taken the histogram of some continuous data. What is the original data? What are the numbers in the rang 2.1 - 2.199 that occurred 43 times? And besides, the freq data you gave cannot replicate the shape of the histogram you gave so you can NOT "creat a histograme which would be exaclty same as figure I have attached" .

[amberly hadden]

Here is the orignal data set. I have created the ranges lets say 2.1-2.199 and counted numbers in series above 2.1 adn next 2.2-2.299 and again counted numbers above 2.2 and so on to get frequency

2.745 2.422 2.876 2.477 2.440 2.674 2.600 2.450 2.630 2.439 2.432 2.483 2.652 2.255 2.448 2.441 2.447 2.537 2.440 2.671 2.502 2.421 2.438 2.582 2.943 2.387 2.221 2.243 2.214 2.187 2.242 2.426 2.385 2.260 2.647 2.595 2.219 2.471 2.495 2.256 2.133 2.225 2.215

[Kelly Kearney]

x = [2.745 2.422 2.876 2.477 2.440 2.674 2.600 2.450 2.630 2.439 ...
     2.432 2.483 2.652 2.255 2.448 2.441 2.447 2.537 2.440 2.671 ...
     2.502 2.421 2.438 2.582 2.943 2.387 2.221 2.243 2.214 2.187 ...
     2.242 2.426 2.385 2.260 2.647 2.595 2.219 2.471 2.495 2.256 ...
     2.133 2.225 2.215];

xedge = 2.1:0.1:3;
n = histc(x, xedge);
bar(xedge, n, 'histc');