How to convert the image into a binary image?

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Manoj Kumar le 21 Juil 2014
Commenté : Image Analyst le 11 Nov 2016
HI, I have a GUI in which I can select multiple regions of interest for an image. I have selected 3 regions in the image. I tried to get the binary image consisting of 3 regions. But unfortunately, I could get only the last(third) region that i selected.
These are the selected regions of interest in the image one by one using the following code.
global segmentedImage
if(size(segmentedImage,3)==3)
im6=rgb2gray(segmentedImage);
else
end
hFig=figure;
finalImage = segmentedImage;
finalImage(:,:) = 0;
choice = 1; % =2 represents it is done
while(choice == 1)
% Display the image in Grayscale to draw the contour
figure;imshow(im6);
% Enlarge figure to full screen.
set(gcf, 'units','normalized','outerposition',[0 0 1 1]);
% axis on;
message = sprintf('Draw CONTOUR line.\nLeft click mouse and hold to begin drawing.\nRelease the mouse button to finish');
uiwait(msgbox(message));
hFH = imfreehand();
% Create a binary image ("mask") from the ROI object.
subplot(1,2,1);
imshow(im6);
title('Original Image','FontSize',fontSize);
% Get coordinates of the boundary of the freehand drawn region.
structBoundaries = bwboundaries(binaryImage2);
xy=structBoundaries{1}; % Get n by 2 array of x,y coordinates.
x = xy(:, 2); % Columns.
y = xy(:, 1); % Rows.
subplot(1, 2, 1); % Plot over original image.
hold on; % Don't blow away the image.
plot(x, y, 'LineWidth', 2);
drawnow;
% Mask the image using bsxfun() function
maskedImage = bsxfun(@times, im6, cast(binaryImage2, class(im6)));
subplot(1,2,2);
% axis on;
title('Regions to be included', 'FontSize', fontSize);
promptMessage = sprintf('Do you want to accept this,\nor draw more regions it?');
titleBarCaption = 'Continue?';
button = questdlg(promptMessage, titleBarCaption, 'Accept', 'More', 'Accept');
if strcmpi(button, 'More')
else
break;
end
close(gcf);
end
close(hFig);
%figure;imshow(finalBinaryImage);
axes(handles.axes2);
imshow(finalImage);
This is the binary Image that i got using the following code:
Where "binaryImage in the above code" is the binary image of the original image . Here is the attachment of the binary image.
I tried to remove the binary image of the multiple regions(binaryImage2) with the binary image of the original segmented Image(binaryImage). But I couldn't get the appropriate result.
Thanks...
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Image Analyst le 21 Juil 2014
You need to initialize a binary image and then OR in the ones from the loop. Before the loop
finalBinaryImage = false(size(im6));
Then in the loop
finalBinaryImage = finalBinaryImage | binaryImage2;
When the loop is done, finalBinaryImage will have all the regions you drew.
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Image Analyst le 21 Juil 2014
What image do you want as the final output? A gray image with black holes burned into it? A binary image with all the regions you outlined? Three separate binary images?
Manoj Kumar le 22 Juil 2014
I need a binary image with all the regions outlined...

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Plus de réponses (2)

Peyman Obeidy le 11 Nov 2016
Greeting I am also interested in doing the same things, did you manage to get all your 3 ROIs on the image. If so, may I get the complete code. This will save me a lot of time.
Cheers Peyman
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Walter Roberson le 11 Nov 2016
Peyman Obeidy comments to Image Analyst:
were is the start point, I am not use to GUI at all
Image Analyst le 11 Nov 2016
Peyman, the code is in the original poster's question at the very top. If, some some unreasonable reason, you're unable to use a GUI, then you can't do this at all, because imfreehand() requires a GUI so you can draw on an image.

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Peyman Obeidy le 11 Nov 2016
Dear Image analyser,
what I would like to do is to a- open an image b- select multiple regions c-display selected region on the original image d- calculate the area of each region
for a-b, I found "Multi ROI/Mask Editor Class (https://au.mathworks.com/matlabcentral/fileexchange/31388-multi-roi-mask-editor-class)" GUI, but I can't get the binary and original image as and output into the workspace.
Maybe I get some help with this, I can manage to do the 'c-d' part by myself.
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