Effacer les filtres
Effacer les filtres

merge cells into a single one

2 vues (au cours des 30 derniers jours)
Qifan
Qifan le 28 Juil 2014
Commenté : dpb le 28 Juil 2014
I have a number of cells h={cell1; cell2; cell3;...cell100}, each cell contains one row but multiple columns (1*n, n varies across cells). Now I want a single cell g contain one row and the sum(n) columns. The basic method is g=[h(1) h(2) h(3) ... h(100)]. Since there are so many cells, it is not convenient to type all. Is there any effective way to make this by exploiting the index? Many thanks.
  1 commentaire
Qifan
Qifan le 28 Juil 2014
A simple transpose function works for cell array.

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Réponses (2)

Azzi Abdelmalek
Azzi Abdelmalek le 28 Juil 2014
If your data looks like
v={1:3 10:20 4 100:105}
out=cell2mat(v)
  1 commentaire
Qifan
Qifan le 28 Juil 2014
Thanks, but actually I have h={1:3; 10:20; 4; 100:105} and I want to have the v you mentioned. The basic way is just too inconvenient to type.

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dpb
dpb le 28 Juil 2014
Modifié(e) : dpb le 28 Juil 2014
c={cell2mat(c)};
...h={1:3; 10:20; 4; 100:105}
Well, you didn't say that in the original. But the answer is the same excepting you must transpose c --
c={cell2mat(c.')};
I returned it as a cell, Azzi just left it as the array; your choice of which you want.
  2 commentaires
Qifan
Qifan le 28 Juil 2014
The transpose function works, but thanks for the help.
dpb
dpb le 28 Juil 2014
.' is the transpose function as was pointed out that's what you needed to do once you revealed you had a column array instead of row. The ' operator is the complex conjugate transpose; for the cell array orientation the accidental use of ' instead of .' does no harm as it doesn't operate on the cell content, but it's a poor habit to get into.

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