How can I write a for loop to do algebra over multiple arrays?

I have 4 1x28 arrays.

I want to solve an equation for time, also linearly spaced as 1x28, for each value in this row.

a = linspace(3,28,28);

b = linspace(4,28,28);

c = linspace(5,28,28);

d = linspace(6,28,28);

time = linspace(1,28,28);

for i = 1:28:

value = a.*time ./ (c+d)

end

So, in the end, value should be a 28x28 array right. The first column of value, for example, should be value evaluated at time 1.

As it goes downward in column 1, it should be evaluated at time 2, etc till 28.

I'm not sure how to actually implement this. When I am doing it regularly, I get back a 1x28 array from value.

Does anyone know the approach or solution I am looking for?

Answer 1

[Wan Ji]

Do loop with indices of t:

a = linspace(3,28,28)';
b = linspace(4,28,28)';
c = linspace(5,28,28)';
d = linspace(6,28,28)';
time = linspace(1,28,28);
value = zeros(28,28);
for i = 1:28
   value(:,i) =  a.*time(i)./ (c+d);
end

And then the value becomes 28*28 as you want.

[Havi Tripathi]

Thanks for the quick help! I understand indexing better now.

Answer 2

[Simon Chan]

Try this:

A = arrayfun(@(x) x.*time./(c+d), a, 'UniformOutput', false)
result = cell2mat(A')