Effacer les filtres
Effacer les filtres

problem in command window : "Subscript indices must either be real positive integers or logicals"

2 vues (au cours des 30 derniers jours)
how do i resolve this??
function [ x] = zignrinv(c )
v=9.91256303526217e-3;
r=3.442619855899;
x(0)=(v/(nrmlpdf( r )));
x(1)=r;
x(c)=0;
for i=2:c
x(i)=sqrt(-2*log((v/x(i-1))+nrmlpdf(x(i))))
end
for i=0:c
zigr(i) =(x(i+1)/x(i));
end
end
and the function "nrmlpdf" is as folows;
function [ y ] = nrmlpdf( x )
y=exp(-x^2/2);
end

Réponse acceptée

Steven Lord
Steven Lord le 21 Août 2021
There's no such thing as element 0 of an array in MATLAB. The first element of an array is element 1. Therefore line 4 of your function cannot work.
Modify your code so it uses 1-based indexing not 0-based indexing.
  3 commentaires
Steven Lord
Steven Lord le 21 Août 2021
The last element of x to which your first for loop assigns is x(c). Your second for loop tries to access x(c+1) which doesn't exist. As written the last element you could create in the vector zigr is element zigr(c-1).
If x was a 5 element vector:
x = 1:5;
what would you expect zigr(5) to be and why? zigr(4) would be 5/4.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by