Access data from table and assign to variables

Hi, I am making a program with excel file already converted to table and now I need to code such that when a user gives an input a certain coloumn is taken and then assign certain variables to some particular blocks in that row.
example:
Vehicle speed fuel
Car 50 2
Bike 20 1
Cycle 5 0
Like user gives input as Bike. then I need to assign variables created like speed and fuel to use in further equations.

4 commentaires

What type of variable do you want to create? A new table? Add a row to an existing table? A new instance of a class variable? A new structure, perhaps added onto an existing structure array?
No changes to the table . I want to extract other values like speed and fuel based on the input given by user(eg Bike). and use them for further calculations.
Stephen23
Stephen23 le 27 Août 2021
"...then I need to assign variables created like speed and fuel to use in further equations."
Why not just access the data directly from the table?
thank you for answering its clear now

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 Réponse acceptée

Ive J
Ive J le 27 Août 2021
Modifié(e) : Ive J le 27 Août 2021
This might work
tab = table({'Car'; 'Bike'; 'Cycle'}, [50; 20; 5], [2; 1; 0],...
'VariableNames', {'Vehicle', 'speed', 'fuel'})
tab = 3×3 table
Vehicle speed fuel _________ _____ ____ {'Car' } 50 2 {'Bike' } 20 1 {'Cycle'} 5 0
filterIn = 'Bike'; %input('what to filter? ', 's');
idx = ismember(tab.Vehicle, filterIn);
if ~any(idx)
fprintf('oops, not found!\n')
return
end
dataTable = tab(idx, :);
dataStruct = table2struct(dataTable, 'ToScalar', true);
as table:
disp(dataTable)
Vehicle speed fuel ________ _____ ____ {'Bike'} 20 1
or struct:
disp(dataStruct)
Vehicle: {'Bike'} speed: 20 fuel: 1

2 commentaires

after getting this is there a way we can assign say x = speed i.e x = 20. x is already defined
Thank you for this.
Ive J
Ive J le 27 Août 2021
Modifié(e) : Ive J le 27 Août 2021
Yes you can easily assign struct fields to variables, but it's better to use structs as they are, it's much easier and more clear!
x = dataStruct.speed; % or other field names, see fieldnames help

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Plus de réponses (1)

Picking up from @Ive J's example, but use 'Vehicle' as Row Labels to take advantage of native table indexing:
t = table([50; 20; 5], [2; 1; 0], 'VariableNames', ["speed", "fuel"], 'RowNames', ["Car"; "Bike"; "Cycle"])
t = 3×2 table
speed fuel _____ ____ Car 50 2 Bike 20 1 Cycle 5 0
t("Bike", ["speed", "fuel"]) % or if you want all variables, t("Bike", :)
ans = 1×2 table
speed fuel _____ ____ Bike 20 1

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