Unable to perform assignment because the left and right sides have a different number of elements.

Hi all,

I am trying to divide a line as attached into 3 main increments which each has different thickness (size)

then divide the 3 increments into 3 sub increments

So I would like my the following results

t(i) =[5 10 20]

and my sub_t should be = [0 2.5 5 5 7.5 10 10 15 20 ]

clear all;
clc;
increments=[5 5 10]
t=0
for i=1:3   
    t(i)=t+increments(i)
    %sub_t=linspace(t(i),t(i+1),3) could be     
end

Answer 1

[Chunru]

increments=[5 5 10]

increments = 1×3

5 5 10

t0=0;
t = zeros(size(increments));
sub_t = [];
for i=1:3   
    %t(i)=t+increments(i)
    t(i)=t0+increments(i);
    sub_t=[ sub_t linspace(t0,t(i),3)];
    t0 = t(i);
end
t

t = 1×3

5 10 20

sub_t

sub_t = 1×9

0 2.5000 5.0000 5.0000 7.5000 10.0000 10.0000 15.0000 20.0000

[sci hub]

@Chunru

Thanks for your comment, however,I need the t

to be a vector array contains the three numbers

Also, I am still looking for the sub_t values should be = [0 2.5 5 5 7.5 10 10 15 20 ]

Hope you could help!

[Chunru]

See the updated.

[sci hub]

@Chunru

Ok for t

but how could I have a vector of sub_t with all the 9 values ??

I tried to add a new loop with 9 but not working

i need my sub_t(i)=[0 2.5 .. 20 ]

Thanks again

[Chunru]

See the update.