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How to use dlgradient for computing second derivative?

22 vues (au cours des 30 derniers jours)
Rahul Gulati
Rahul Gulati le 10 Sep 2021
The following code gives me an error.
x0 = dlarray([-1,2]);
[fval,gradval] = dlfeval(@rosenbrock,x0)
function [y,dy2dx] = rosenbrock(x)
y = 100*(x(2) - x(1).^2).^2 + (1 - x(1)).^2;
dydx = dlgradient(y,x);
dy2dx= dlgradient(dydx,x);
end
I am using dlgradient to compute the second derivative but getting the following error:
"Error using dlfeval (line 43)
Value to differentiate must be a traced dlarray scalar."
Any help on what am i doing wrong? Thanks.

Réponse acceptée

Abolfazl Chaman Motlagh
Abolfazl Chaman Motlagh le 10 Sep 2021
Hi, You are using dlgradient wrong, first agument of dlgradient should be scalar. after 1 gradient from y respect to x. gradient return 1by2 vector. they are and . so you cannot use dydx again in dlgradient. also for second derivative you have 4 elements : , , ,
also you should specify option EnableHigherDerivatives in dlgradient.
so substiture your function with this :
function [y,dy2dx] = rosenbrock(x)
y = 100*(x(2) - x(1).^2).^2 + (1 - x(1)).^2;
dydx = dlgradient(y,x,'EnableHigherDerivatives',true);
dy2dx(1,1:2)= dlgradient(dydx(1),x);
dy2dx(2,1:2)= dlgradient(dydx(2),x);
end
  5 commentaires
Abolfazl Chaman Motlagh
Abolfazl Chaman Motlagh le 10 Sep 2021
Glad to help .
Sanaz Zanjani Foumani
Sanaz Zanjani Foumani le 29 Déc 2021
Do you know how I can use dlgradiet in fmincon? I mean I want to use automatic derevative in fmincon insted of analytical derevative.

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