How to evaluate vector function defined in 2D with meshgrid?

10 vues (au cours des 30 derniers jours)
Yonghyeon Jeon
Yonghyeon Jeon le 19 Sep 2021
Réponse apportée : darova le 19 Sep 2021
Hi, guys.
I would like to evaluate and get the function values of vector function defined in 2D.
For example, we assume that we have the function defined in 2D and discretized domain.
These are coded in matlab as follows:
fun = @(x, y) [sin(x) .* sin(x) ; cos(x) .* cos(y)];
xgrid = linspace(0, pi, 3);
ygrid = linspace(0, pi, 4);
[xmesh, ymesh] = meshgrid(xgrid, ygrid);
So, the result that I want is the 3-dimensional matrix such as
result(:,:,1) = [0, 1, 0 ; 0, 1, 0 ; 0, 1, 0 ; 0, 1, 0];
result(:,:,2) = [1, 0, -1 ; .5, 0, -.5 ; -.5, 0, .5 ; -1, 0, 1];
I tried
fun(xmesh, ymesh)
but it didn't give me the wanted result.
Plese give me a novel advises.

Réponses (1)

darova
darova le 19 Sep 2021
Try cat
fun = @(x, y) cat(3, sin(x).*sin(x), cos(x).*cos(y));

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