error getting eigenvalues varying with time

3 vues (au cours des 30 derniers jours)
PetronasAMG
PetronasAMG le 4 Oct 2021
Commenté : Rena Berman le 5 Nov 2021
xcg = 0.15; rea = 0.5; xe = 0.35; cla=2*pi ; m= 5*pi; a0 = 0; wr = (1/2); mu = 1+(3*a0^2);
U = 0:0.01:1;
a1 = ((mu*((U.*cla)/2*m))*(/(1-(xcg^2/rea^2)); a2 = wr^2/(1); a3 = ((mu*((U.^2*cla)/2*m)*/(1-(xcg^2/rea^2)); b1 = (1-((mu*((U.^2*cla)/2*m))/(1-(xcg^2/rea^2)); b2 = ((-mu*((U.*cla)/2*m))*/(1-(xcg^2/rea^2)); b3 = (-wr^2*(xcg/rea^2))
A = [a2 1 0 a1;0 2 5 0;0 0 b3 1;0 -b2 -b1 0];
nt = length(U); v = zeros(4,4,nt); d =zeros(4,1,nt);
for i = 1:nt [V,E] = eig(A); v(:,:,i) = V; d(:,1,i) = diag(E); end I am trying to get eigen valuse and vectors from corresponding time, but running into an error Error using vertcat Dimensions of arrays being concatenated are not consistent. A = [a2 1 0 a1;0 2 5 0;0 0 b3 1;0 -b2 -b1 0];
any suggestions? Also since I am getting two lambda (each being +/-) how would i be able to plot these eigenvaluse respect to U? please help!
  1 commentaire
Rena Berman
Rena Berman le 5 Nov 2021
(Answers Dev) Restored edit

Connectez-vous pour commenter.

Réponse acceptée

Walter Roberson
Walter Roberson le 4 Oct 2021
You need to fix a1, which has the invalid syntax (/( and is missing two )
You need to fix a3, which has the invalid syntax */ and is missing two )
You need to fix b1, which is missing two )
You need to fix b2, which has the invalid syntax */ and is missing one )
Please recheck a2, which divides by 1: explicit division by 1 is confusing, suggesting that something went missing
xcg = 0.15; rea = 0.5; xe = 0.35; cla=2*pi ; m= 5*pi; a0 = 0; wr = (1/2);
mu = 1+(3*a0^2);
U = reshape(0:0.01:1, 1, 1, []);
nU = numel(U);
sU = size(U);
a1 = ((mu*((U.*cla)/2*m))*(/(1-(xcg^2/rea^2));
a2 = repmat(wr^2/(1), sU);
a3 = ((mu*((U.^2*cla)/2*m)*/(1-(xcg^2/rea^2));
b1 = (1-((mu*((U.^2*cla)/2*m))/(1-(xcg^2/rea^2));
b2 = ((-mu*((U.*cla)/2*m))*/(1-(xcg^2/rea^2));
b3 = repmat((-wr^2*(xcg/rea^2)), sU);
A = [a2 ones(sU) zeros(sU) a1;
2*ones(sU) 5*ones(sU) zeros(sU);
zeros(sU) zeros(sU) b3 ones(sU);
zeros(sU) -b2 -b1 zeros(su)];
v = zeros(4,4,nU);
d =zeros(4,1,nU);
for i = 1:nU
[V,E] = eig(A(:,:,i));
v(:,:,i) = V;
d(:,1,i) = diag(E);
end

Plus de réponses (0)

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Produits


Version

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by