using median() instead of medfilt2()

I am not sure how to do part b and well hence c as well. can you help with how to code this

my teacher requested using median()

i attached the image file

%% 2. Median Filter
sad1=imread('sadimg.bmp');                                  %a) Read ‘sadimg.bmp’ store image into ‘sad1’ 

median_filt=      

[Rena Berman]

(Answers Dev) Restored edit

Answer 1

[Walter Roberson]

Read the function information at https://www.mathworks.com/help/images/ref/blockproc.html more closely.

Hint: Use a 1 x 1 block and a border of [1 1]

Hint: Use TrimBorder false

[Walter Roberson]

Look at the documentation on blockproc. Notice that one of the parameters is an anonymous function that receives a struct and accesses a field of that struct and passes the data to a function to be processed.

@(SOMETHING) median(SOMETHING.APPROPRIATE_FIELD(:))

[Image Analyst]

blockproc normally moves in "jumps" of the block size when it scans the image. However it can move with an overlap, so that it would move over by just one pixel if you want. I attach demos for both ways.

However I think that if you want to move over just one pixel at a time, then the function you should probably use instead would be nlfilter(). You can have a custom filter where you did a median with the median() function. Demo attached for that also.

Answer 2

[Image Analyst]

See our discussion in your duplciate post:

https://www.mathworks.com/matlabcentral/answers/1466294-5-x-5-median-filter-with-out-inbuilt-function#comment_1767564