I have
a =
1 2 3 4
5 6 7 8
9 10 11 12
I need to covert it to a column vector keeping the input order as follows,
b =
1
2
3
4
.
.
12
But when you use reshape funtion
b = [reshape(a,[12,1])]
b =
1
5
9
2
6
10
3
7
11
4
8
12
Can anyone help me on this?

Réponses (1)

Star Strider
Star Strider le 9 Oct 2021
Transpose ‘a’ before calling reshape
a = [1 2 3 4
5 6 7 8
9 10 11 12];
b = reshape(a.',[],1)
b = 12×1
1 2 3 4 5 6 7 8 9 10
.

2 commentaires

Hingure Kadurugamuwa
Hingure Kadurugamuwa le 9 Oct 2021
Thanks a lot Star Strider
It worked
Star Strider
Star Strider le 9 Oct 2021
My pleasure!
If my Answer helped you solve your problem, please Accept it!
.

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