Binary to ASCII Conversion
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Hi,
I have message of 1x5120 double (binary values 0 and 1). I have to convert this to ASCII. I am supposed to use below method. Can anyone let me know what is the error in the below code, Thanks.
ASCII_1 = Message(1,1:10)*(2.^[0:9])';
u = Message(1,Nsc+1:end);
wh=2.^[6:-1:0];
m=char(u(1:7)*wh');
for k=1:1:ASCII_1
m=[m char(u(7*(k-1)+1:7*k)*wh')];
end
disp(m)
Note: Message is 1x5120 double
5 commentaires
David Hill
le 9 Oct 2021
You need to know how the message was transmitted for example:
a='cat in hat';
t=dec2bin(double(a),8)';%we are assuming each character is forced to be 8 bits (it is important to know)
t=t(:)'-'0';%we are assuming this is the stream you are getting, but it could be flipped depending on how it was transmitted.
If the above is the case, decoding is as simple as:
r=num2str(t);
r=char(bin2dec(reshape(r(r~=' '),8,[])'))';
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