why is my code giving me a parse error

this is my code:

x=0.1;

beats=A(1,30);

for k=1:30

A=2x*(1-x);

x=A;

disp(A)

end

when i run this i get a parse error and A undefined

I am not familiar enough with MATLAB syntax to figure out what it even means, let alone how to fix it. Any ideas? Thank you!

Answer 1

[David Hill]

x=0.1; 
%beats=A(1,30);  There is no A defined and you are indexing into it!
for k=1:30
 A(k)=2*x*(1-x); %need 2*, if you want to keep track of all iterations, index into A
 x=A(end); 
 %disp(A) 
end
disp(A);%display outside loop

[zidan masood]

how do i define A please?

[David Hill]

I code above runs. You never used beats. What where you trying to do with beats?

[zidan masood]

this is my question

The heart beat rate has to be well regulated to provide enough oxygenated blood throughout the body and so depends on feedback with the body’s oxygen demand. A simple discrete model of heart beat regulation is given by:

xt+1 = kxt(1 - xt)

Here xt represents the normalised heart beat rate at time t recorded once per minute. That is, the normalisation involves dividing the actual hear rate in beats per minute by 80 beats per minute. The parameter k is a positive real number (hopefully) greater than 0

a) Write a MATLAB program using array operations to generate a table (with headings) of the normalised heart beat rate per minute starting at time t = 0 with the value of x0 entered by the user. Run your program with the maximum time set to 30 minutes. Show table and MATLAB code for x0 = 0.1 and k = 2

[David Hill]

I will get you started

HeartRate=.1;
Time=0;
t=table(Time,HeartRate);
%your loop
for k=1:30
  t.Time(k)=k+1;
  t.HeartRate(k)=
end