write down matlab command lines into python

I am trying to write small part of command lines into python as I am still new and not sure if I am able to do so or not,

clc
z=4;
nu_z=1;
t_MF             =      [0.1,.12,.2]
t_ID             =      [1,2,1,1]
x                =       z*nu_z;                                  
r                =       0;
p                =       zeros(1,x);
for i = 1:z
    for j = 1:nu_z
    p(r+j)      =       t(D(i))/nu_z;  
    end 
    r           =        r+nu_z; 
end

I tried with python as the following but I got the following error:

I got the following error: IndexError: index 8 is out of bounds for axis 0 with size 8

import numpy as np
 z               =       4
 nu_z            =       2
 x               =       z*nu_z
 r               =       0
 t               =       np.array([0.1,.12,.2])
 D               =       np.array([0,1,0,0])
 p               =       np.zeros((1,x))
 for i in range(z):
     for j in range(nu_z):
         print(j)
         p[r+j]   =       t[D[i]]/nu_z
         r        =        r+nu_z 

[Walter Roberson]

The assignment to r should be outside of the inner for loop.

[Mark Sc]

@Walter Roberson

Thank you so much for your comment, I agree with you about that, but the problem in python as I am new not sure how could I apply that without end , Is the same as below ??? even though still got a wrong answer ?

Please let me know your suggestion if you are familiar with python,

import numpy as np
 z               =       4
 nu_z            =       2
 x               =       z*nu_z
 r               =       0
 t               =       np.array([0.1,.12,.2])
 D               =       np.array([0,1,0,0])
 p               =       np.zeros((1,x))
 for i in range(z): 
     r        =        r+nu_z 
     for j in range(nu_z):
         print(j)
         p[r+j]   =       t[D[i]]/nu_z
 
         

[Walter Roberson]

I have rarely used python, so I am not certain, but I think it would be

import numpy as np
 z               =       4
 nu_z            =       2
 x               =       z*nu_z
 r               =       0
 t               =       np.array([0.1,.12,.2])
 D               =       np.array([0,1,0,0])
 p               =       np.zeros((1,x))
 for i in range(z):
     for j in range(nu_z):
         print(j)
         p[r+j]   =       t[D[i]]/nu_z
     r        =        r+nu_z 

[Mark Sc]

@Walter Roberson

it's correct,

you saved me

thank you so much

How could I accept your answer

Answer 1

[Walter Roberson]

I have rarely used python, so I am not certain, but I think it would be

import numpy as np
 z               =       4
 nu_z            =       2
 x               =       z*nu_z
 r               =       0
 t               =       np.array([0.1,.12,.2])
 D               =       np.array([0,1,0,0])
 p               =       np.zeros((1,x))
 for i in range(z):
     for j in range(nu_z):
         print(j)
         p[r+j]   =       t[D[i]]/nu_z
     r        =        r+nu_z