calling a function n times

say I have a function called myfun which has no arguments but returns a number, and I call it and assign the value to 'y', like

y=myfun()

now say I want to call it 'n' times to get a vector 'y' with 'k' entries. Ive tried

k=(1:10);
y(k)=myfun();

but this does not work, what do I do?

p.s. my exact function code is

function [critical_region] = rubbish()
Y=sort(randn(50000,100));
Z=zscore(Y);
n = size(Y,1);
j = 1:n;
result = -n-(1/n)*sum(bsxfun(@times,j.'*2-1, log(normcdf(Z,0,1))+log(1-normcdf(Z(end:-1:1,:),0,1))));
critical_region = prctile(result,[85, 90, 95, 97.5, 99]);

Answer 1

[Walter Roberson]

for k=1:10
  y(k) = myfun();
end

[john birt]

that produced an error

??? In an assignment A(I) = B, the number of elements in B and

I must be the same.

Error in ==> rubbish2 at 2

t(k) = rubbish();

[Walter Roberson]

Your initial description said that the function returns a number, but it does not: it returns a vector of numbers. Adjusting for that, and with the premise that it will always return the same number of elements:

for k=1:10

y(k,:) = myfun();

end

Answer 2

[Andrei Bobrov]

function critical_region = yourfun
  Y=sort(randn(500,10));
  Z=zscore(Y);
  q=size(Y);
  result =  -q(1)-(1:2:q(1)*2)*(log(normcdf(Z,0,1))+log(1-normcdf(Z(q(1):-1:1,:),0,1)))/q(1);
  critical_region = prctile(result,[85, 90, 95, 97.5, 99]);
end

for i1 = 10:-1:1
  y(i1,:) = yourfun;
end