creating multiple variables from a vector

i have a vector [185 186 188 189 192 247 248 249 250 251 252 253 254 255 625 626....] i want to group all of terms that are within 15 numbers apart together. for example vector1 = [185 186 188 189 192] vector2= [247 248 249 250 251 252 253 254 255] vectorn = [625 626....]

Answer 1

[Geoff Hayes]

Shobhit - rather than creating multiple variables (which is possible but gets messy), why not just create a cell array of these vectors instead? That way you have all of the vector data within one array.

 % create the vector of data to break apart
 V =  [185 186 188 189 192 247 248 249 250 251 252 253 254 255 625 626];

 % sort the data in ascending order
 V = sort(V);

 % create the data vector cell array
 data = {};
 k    = 1;

 % continue looping until all elements have been split into vectors
 while true
     % find the index of the first element that is 15 larger than the first V(1)
     idx = find(V>V(1)+15,1);

     if ~isempty(idx)
          % extract the elements
          data{k} = V(1:idx-1);

          % reset V, removing those that have been extracted
          V        = V(idx:end);

          % increment to the next k
          k        = k + 1;
     else
         % else there is no element in V that is 15 larger, so all remaining
         % elements are together
         data{k} = V(1:end);

         % break out of loop
         break;
     end
 end

Try the above and see what happens!

[shobhit mehrotra]

Worked thank you!

Answer 2

[Guillaume]

An alternative way of doing this:

[~, binnumber] = histc(V, min(V):15:max(V)+15);
vector = cell(1, max(binnumber)); %optional
for bin = 1:max(binnumber)
   vector{bin} = V(find(binnumber == bin));
end

Answer 3

[Andrei Bobrov]

EDIT

a = [185 186 188 189 192 247 248 249 250 251 252 253 254 255 625 626] ;

m = ceil(max(a))+1;
k = min(a):15:m;
k(end) = m;
[~,ii] = histc(a,k);
ii = cumsum([1;diff(ii(:))~=0]); % OR [~,~,ii] = unique(ii);
out = accumarray(ii(:),a(:),[],@(x){x})