Use of break in if?

Here is my code i Want to use break/continue after First if Ends. as i have mention it there. but we cant use break in IF. I need alternative of it. Note: there are two times if(Stroke_counter==1) in code. that is not because of mistake

    if(Stroke_counter==1)        
        if (((S==1)||(E==1)) &&( (y==2)) )                    
                    msgbox('This is One','Recognize');
                    end                                            
        elseif( (x==1)&&(y==1)&&(x==1) &&(y==1) &&(S==2))                           
                    msgbox('This is two','Recognize');
                    end                    
        elseif((x==1)&&(y==1)&&(x~=1))
                    msgbox('This is three','Recognize');
                    end
         beak;
        else
                    msgbox('Not Found...','error');  
        end
    else
        msgbox('Not in 1 step','error');  

    end

    if(Stroke_counter==1)        
        if (((S==1)||(D==1)) &&( (y==2)) )                    
                    msgbox('This is four','Recognize');
                    end                                            
        elseif( (x==1)&&(y==1)&&(D==1) &&(y==1) &&(S==2))                           
                    msgbox('This is five','Recognize');
                    end                    
        elseif((x==1)&&(F==1)&&(x~=1))
                    msgbox('This is Six','Recognize');
                    end
        else
                    msgbox('Not Found...','error');  
        end
    else
        msgbox('Not in 2 step','error');

[David Sanchez]

What is the point on using a break within an if statement?

If the condition is fulfilled, the following else will not count in your code anyway.

[Lorenzo TORRICELLI]

For example, if a block of instructions is common to a number of conditions, whereas a certain case is exceptional.

Answer 1

[Adam]

If you want to break after the first If ends then you won't be in the If to place your break/continue. And if you were able to place one there then why not just delete the second if since it would never execute.

[Adnan Ali]

Actually my code is too much complex this is just as example. and MAtlab donot work in more than 6 (if() elseif() else end).

So i divided it in 3 by 3 portions. but if answer found in 1st portion then no need of execution of 2nd portion. thats why i need break/ continue.

[Adam]

Just use a boolean then as

answerFound = false;

then update it in each if statement and then AND it together with the following if statements as e.g.

if( ~answerFound  && Stroke_counter==1)

To be honest though this sounds like such a large block of code it should be a function by itself (probably many, but that's a side issue) so you can just put

return

to return early from the current function and then carry on your algorithm in the function that calls this one.

[Adnan Ali]

return is working. but truly speaking I found matlab behavior too much annoying in this case. Thanks for your Help.

Answer 2

[Jan]

"MAtlab donot work in more than 6 (if() elseif() else end)" - of course Matlab handles much more nested IF branchs than 6.

Checking a lot of different conditions with a pile of IF commands creates code, which is hard to read and to debug. It is too prone to typos like in your code:

((x==1) && (y==1) && (x~=1))

This cannot be TRUE, because x==1 && x~=1 cannot happen. So it is not Matlab, but the programming style, which causes problems here.

This is not useful also:

elseif( (x==1) && (y==1) && (x==1) && (y==1) &&(S==2)) 
%                           ^^^^^^^^^^^^^^^^ tested twice ?!

Your code is not valid at all due to the orphand end commands:

        if (((S==1)||(E==1)) &&( (y==2)) )                    
                    msgbox('This is One','Recognize');
                    end  % <== Nope, no END before ELSEIF
        elseif