convolution of the two image
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TULIKA
le 23 Août 2014
Commenté : Image Analyst
le 23 Août 2014
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/145180/image.jpeg)
i have to code convolution of the two image(the greyimage output and the image i posted)(once in space domain and again in frequency domain using fft2 and ifft2)there is no error in the code but it didn't give proper output...please let me know where i'm going wrong in the coding...
x= 1:256;y=1:256;
[p,q]=freqspace(256);
[X,Y]=meshgrid(p,q);
R=(X.^2 + Y.^2);
Lambda=10*10^-9;
dis=4*10^-2;
F = (exp(i.*pi.*R))./(Lambda.*dis);
grayImage = imag(F);
mesh(grayImage);
imshow(grayImage, []);
colormap(gray(256));
A=imread('image.jpg');
R=A(:,:,1);
G=A(:,:,2);
B=A(:,:,3);
igray=rgb2gray(A);
A1=im2double(igray);
I=conv2(A1,grayImage);
figure,imshow(I,'InitialMagnification','fit');
2 commentaires
Image Analyst
le 23 Août 2014
Please attach image.jpg or give us a standard demo image we can use instead.
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Image Analyst
le 23 Août 2014
This seems like two separate programs - the top half does stuff with F, then the bottom half ignores F and does stuff with image.jpg and gray scale versions of it. Are they supposed to be related in anyway? You're basically convolving A with itself, which is the autocorrelation and will give you a strong central spike with steep sides. What do you think the proper output should be? Are you sure you want an autocorrelation of A or do you want to convolve A with F? Please supply more information and images.
5 commentaires
Image Analyst
le 23 Août 2014
Well the main reason you didn't get any good display is because you didn't use [] in imshow so any values more than 1 just got clipped to 1. Several other problems/issues (though nothing major though and some just a matter of style), so I just did it correct from scratch.
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