How do I confront the value of a matrix?

1 vue (au cours des 30 derniers jours)
HelpAStudent
HelpAStudent le 11 Oct 2021
Modifié(e) : DGM le 11 Oct 2021
Hi, I have a matrix 21x6
I have for rows 16:20 confront the column:
for example for the first rows to analyze: (ROW 16)
(Column 4 - Column 1) / 12 = x
(Column 5 - Column 2) / 12 = y
(Column 6 - Column 3) / 12 = z
(x+y+z):3=value16
And after each rows I need the mean of the value printed

Réponse acceptée

DGM
DGM le 11 Oct 2021
Modifié(e) : DGM le 11 Oct 2021
I'm not really sure what this is supposed to mean.
%(x+y+z):3=value16
What guarantees that the sum of x,y,z is less than 3?
I guess you can start with this:
% test array
A = randi(9,21,6)
% get all xyz, sum
xyz = sum((A(16:20,4:6) - A(16:20,1:3))/12,2)
% expand and take mean
mn = zeros(size(xyz));
for r = 1:size(xyz,1)
mn(r) = mean(xyz(r):3);
end
mn

Plus de réponses (0)

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Produits


Version

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by