Effacer les filtres
Effacer les filtres

Calculate the Median of the results from 100 Simulations

1 vue (au cours des 30 derniers jours)
CMatlabWold
CMatlabWold le 13 Oct 2021
Commenté : CMatlabWold le 14 Oct 2021
Hi. I have a code where I am running a Random Forest regression. I am running it 100 times. However, I am having difficulty calculating the median of the 100 trials.
The result I am looking for is located in the variable designated "impOOB".
For each run, there should be values in impOOB variable for 5 columns. For instance:
0.427417559041683 0.00894308188405568 0.141297948087486 0.222153283589539 0.200188127397237
For 100 runs of column 1, I need the median. The same for column 2, and so forth.
My code is as follows:
n = 100;
result = zeros(n,5);
for k=1:n
X = readtable('TOPOonly.xlsx','PreserveVariableNames',true)
Y = readtable('TotalComplaintsRF.xlsx','PreserveVariableNames',true)
t = templateTree('NumVariablesToSample','all',...
'PredictorSelection','interaction-curvature','Surrogate','on');
Mdl = fitrensemble(X,Y,'Method','Bag','NumLearningCycles',200, ...
'Learners',t);
yHat = oobPredict(Mdl);
R2 = corr(Mdl.Y,yHat)^2
impOOB = oobPermutedPredictorImportance(Mdl);
impOOB(impOOB<0) = 0;
impOOB = impOOB./sum(impOOB)
result(k) =
end
I'll attach the files as well. I appreciate very much any help with this.

Réponse acceptée

Matt J
Matt J le 14 Oct 2021
Modifié(e) : Matt J le 14 Oct 2021
impOOB=rand(100,5)
impOOB = 100×5
0.7604 0.5152 0.7196 0.2418 0.5420 0.8386 0.3787 0.4701 0.4692 0.7572 0.9929 0.0561 0.2087 0.1176 0.9434 0.7796 0.2491 0.1337 0.1499 0.9048 0.3695 0.1500 0.6826 0.4575 0.4751 0.6069 0.1207 0.8111 0.5832 0.3273 0.9885 0.2647 0.1840 0.9606 0.0610 0.1243 0.3249 0.5171 0.1649 0.9400 0.7085 0.7869 0.5282 0.5472 0.4634 0.7656 0.4034 0.7932 0.8618 0.5136
median(impOOB,1)
ans = 1×5
0.4813 0.4997 0.4696 0.4513 0.5518
  3 commentaires
Matt J
Matt J le 14 Oct 2021
n = 100;
result = zeros(n,5);
for k=1:n
X = readtable('TOPOonly.xlsx','PreserveVariableNames',true)
Y = readtable('TotalComplaintsRF.xlsx','PreserveVariableNames',true)
t = templateTree('NumVariablesToSample','all',...
'PredictorSelection','interaction-curvature','Surrogate','on');
Mdl = fitrensemble(X,Y,'Method','Bag','NumLearningCycles',200, ...
'Learners',t);
yHat = oobPredict(Mdl);
R2 = corr(Mdl.Y,yHat)^2
impOOB = oobPermutedPredictorImportance(Mdl);
impOOB(impOOB<0) = 0;
result(k,:) = impOOB./sum(impOOB);
end
median(result,1)
CMatlabWold
CMatlabWold le 14 Oct 2021
It works. Thank you very much

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur MATLAB dans Help Center et File Exchange

Produits


Version

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by