Please help me to look at the code below. Thx

I want to get the max and min value of the equation, using the last three lines of code. BuI I don't know what's wrong with the issue.

Answer 1

[Steven Lord]

Change the name of the output variable on line 15. When a variable named min exists you will not be able to call the min function.

In fact if you're looking for the first instance of the minimum value don't use find. Call min with two output arguments.

[Tianlan Yang]

OK, but it is still not work...

[Tianlan Yang]

Can anyone answer this question, plz

[Cris LaPierre]

Clear your workspace. The variable min still exists.

Once you do, it works just fine. I've cleaned the last 3 lines of your code a little.

x=0:0.001:5;
f12 = 8.*(x-pi).^2./((x-pi).^2+1).^3-2./((x-pi).^2+1).^2;

figure
plot(x,f12)

[f12min,index] = min(f12)

f12min = -2.0000

index = 3143

xmin = x(index)

xmin = 3.1420

[Tianlan Yang]

It seems like right. why I am getting another error, I am going to collapsed.

[Tianlan Yang]

I have checked lots of times, I don't have any min variables in my workspace, but it still not works

[Tianlan Yang]

It works thank you so much