Error in Bvp4c

3 vues (au cours des 30 derniers jours)
Priya M
Priya M le 23 Oct 2021
I'm trying to run the following bvp4c MATLAB code, but keep running into an error:
please anyone find out my mistakes and correct me..
Thank you.

Réponse acceptée

Jan
Jan le 23 Oct 2021
You define the variable beta on top of the code, but this does not mean, that it is known in all subfunctions. Pr, gamma and lam are not known inside also.
Either define the constants, where they are needed, or provide them using an anonymous function:
for gamma=0.0:0.25:1
sol = bvpinit(linspace(0,5,50),[0 0 0 0 0 0 0]);
fcn = @(t,y) bvpexam1(t, y, beta, gamma, lam, Pr);
sol1 = bvp4c(fcn, @bcexam1,sol);
...
end
function ysol = bvpexam1(t, y, beta, gamma, lam, Pr)
...
end
  5 commentaires
Jan
Jan le 27 Oct 2021
Modifié(e) : Jan le 27 Oct 2021
f =@(x,y)[y(2);
...
(1/(1+E*y(6)-Pr*gamma*y(1)^2))*(-E*y(7)^2-Pr*y(1)*y(7)+Pr*gamma*y(1)*y(2)*y(7))];
% ^
There is a missing closing square bracket in your code. After adding it I get a result.
Priya M
Priya M le 28 Oct 2021
Thanx a lot sir....

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MOSLI KARIM
MOSLI KARIM le 27 Nov 2023
this code works function d
Pr=0.72;
beta=0.5;
lam=0.2;
E=0.5;
for gamma=0.0:0.25:1
sol = bvpinit(linspace(0,5,50),[0 0 0 0 0 0 0]);
sol1 = bvp4c(@bvpexam1, @bcexam1,sol);
x1 = sol1.x;
y1 = sol1.y;
figure (1)
plot(x1, y1(2,:));
hold on
figure (2)
plot(x1, y1(6,:));
hold on
z = y1(3,1);
p = y1(7,1)'
figure(3)
plot(gamma,y1(7,1),'-bo')
hold on
end
function res = bcexam1(y0, yinf)
res=[y0(1)-0;y0(2)-1;y0(4)-0;y0(6)-1;yinf(2)-0;yinf(4)-0;yinf(6)-0];
end
function ysol = bvpexam1(~,y)
yy1 = (1/(1-beta*y(1)^2))*(-y(1)*y(3)+y(2)^2-2*lam*(y(4)-beta*y(1)*y(5))-2*beta*y(1)*y(2)*y(3));
yy2 = (1/(1-beta*y(1)^2))*(-y(1)*y(5)+y(2)*y(4)+2*lam*(y(2)+beta*(y(2)^2-y(1)*y(3)+y(4)))-2*beta*y(1)*y(2)*y(5));
yy3 = (1/(1+E*y(6)-Pr*gamma*y(1)^2))*(-E*y(7)^2-Pr*y(1)*y(7)+Pr*gamma*y(1)*y(2)*y(7));
ysol = [y(2);y(3);yy1;y(5);yy2;y(7);yy3];
end

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