Why my imaginary graph is straight line?

clc

clear

close all

syms t s I1 I2

% KVL equations

KVL1 = (2*s^2+s+1)*I1-(s+1)*I2 == 1;

KVL2 = (s+1)*I1-(s^2+4*s+1)*I2 == 2;

Eqns = [KVL1 KVL2] ;

Vars = [I1 I2] ;

% Solving equations

Soln = solve(Eqns,Vars) ;

I1(s) = Soln.I1 ;

I2(s) = Soln.I2 ;

% Finding i1(t) and i2(t) using Inverse Laplace Transform

i1(t) = ilaplace(I1(s),s,t) ;

i2(t) = ilaplace(I2(s),s,t) ;

figure

subplot(2,1,1)

fplot(t,real(i1(t)),'LineWidth',1.5)

xlabel('t')

ylabel('Re[i_1(t)]')

title('Real Part of i_1(t)')

grid on

subplot(2,1,2)

fplot(t,imag(i1(t)),'LineWidth',1.5)

xlabel('t')

ylabel('Im[i_1(t)]')

title('Imaginary Part of i_1(t)')

grid on

figure

subplot(2,1,1)

fplot(t,real(i2(t)),'LineWidth',1.5)

xlabel('t')

ylabel('Re[i_2(t)]')

title('Real Part of i_2(t)')

grid on

subplot(2,1,2)

fplot(t,imag(i2(t)),'LineWidth',1.5)

xlabel('t')

ylabel('Im[i_2(t)]')

[John D'Errico]

I'm sorry, but this needs to be said. If it is imaginary, then just pretend it is curved. :)

Answer 1

[John D'Errico]

fplot(t,imag(i1(t)),'LineWidth',1.5)

To my eyes, this does not look straight. But then I may need new glasses.

[Muhammad Na'imullah Fairul Nizam]

Thank you sir