How to get a geometric sequence?

Hi, I have

 tao=1000;
 v=0.9;
 T1=0.01;

I want to have a geometric sequence T, where T1=T2=T3...=T1000 ( since tao=1000)

The first 100 T will be equal to T1,

The second 100 T which starts from T101 until T200= v*T1

The third 100 T ( from T201 until T300 = v*v*T1)

The fourth 100 T (from T301 till T400 = v*v*v*T1)

and so on.

How am I going to get the sequence? Thanks in advance.

[Yokesh]

A = r.^(1:n);

This creates matrix A with geometric sequence with a ratio 'r'

Answer 1

[SK]

Use the .^ operator and matrix multiplication

T = v.^(0:9) * T1;
T = ones(100,1)*T;
T = T(:);

Alternatively (maybe faster)

T = v.^(0:9) * T1;
T = T(ones(1,100), :);
T = T(:);

Answer 2

[the cyclist]

It was not perfectly clear to me what you needed to leave as a variable, and what is a constant. But, this should get you started.

v=0.9;
T1=0.01;

T = T1*ones(100,10);

v_vector = v.^(0:9);

T = bsxfun(@times,T,v_vector)

T = reshape(T,1,1000)