Plotting time series of Velocity over 48 hours

5 vues (au cours des 30 derniers jours)
John Carroll
John Carroll le 25 Oct 2021
Commenté : John Carroll le 25 Oct 2021
I am trying to plot Velocity over a time frame of 48 hours. I have calculated Vm = 5.07. The given Velocity equation is: V(t) = Vm*sin((2*pi*t)/(Ttide));
My code is:
figure(1);
Vm=5.07; % Calculated on Paper
t=[1:1:48]; % Time over 48 hours
V(t) = Vm*sin((2*pi*t)/(Ttide)); % Velocity Equation
plot(t,V(t))
This is outputing a postivie sloping straight line, while I know the line should be sinusoidal.

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Scott MacKenzie
Scott MacKenzie le 25 Oct 2021
Modifié(e) : Scott MacKenzie le 25 Oct 2021
% test value for Ttide (not given in question)
Ttide = 1;
figure(1);
Vm=5.07; % Calculated on Paper
%t=[1:1:48]; % Time over 48 hours
t = linspace(1,48); % use 100 sample points (or more)
V = Vm*sin((2*pi*t)/(Ttide)); % Velocity Equation (NOTE: change V(t) to just V)
plot(t,V)
  2 commentaires
John Carroll
John Carroll le 25 Oct 2021
Thank You!
Is it posible to have this be one line?
Ttide is give as Ttise=12.42 hours the converted to seconds as Ttide=12.42*60*60 (Forgot to mention)
John Carroll
John Carroll le 25 Oct 2021
Ive relized this is where my mistake was made!

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