How to create a block diagonal matrix from the slices of a 3D matrix

6 vues (au cours des 30 derniers jours)
Mohammed
Mohammed le 2 Oct 2014
Commenté : Yunsong Liu le 18 Juil 2019
I have a large 3D matrix (K) composed of 200 slices , and I want to create a block diagonal matrix from the slices of it without looping. For example
K(:,:,1) =[1 2;3 4]
K(:,:,2) =[5 6;7 8]
K(:,:,3) =[9 10;11 12]
.
.
.
K(:,:,200) =[1 10;13 15]
if we assume the number of slice is 3, the output should be
1 2 0 0 0 0
3 4 0 0 0 0
0 0 5 6 0 0
0 0 7 8 0 0
0 0 0 0 9 10
0 0 0 0 11 12
But how the block diagonal matrix created from all the 200 slices without looping?

Réponse acceptée

Azzi Abdelmalek
Azzi Abdelmalek le 2 Oct 2014
k(:,:,1) =[1 2;3 4]
k(:,:,2) =[5 6;7 8]
k(:,:,3) =[9 10;11 12]
q=num2cell(k,[1,2])
blkdiag(q{:})
  4 commentaires
Azzi Abdelmalek
Azzi Abdelmalek le 2 Oct 2014

هذه إحدى التقنيات تعلمتها في هذا المنتدى

Matt J
Matt J le 2 Oct 2014
Note that this still uses a for-loop inside num2cell.m, though how much that hurts you, I don't know.
Note also that my 2nd answer here was the same as this, except that it returns the result in sparse form, which is normally more desirable for block diagonal matrices with small blocks.

Connectez-vous pour commenter.

Plus de réponses (3)

Matt J
Matt J le 2 Oct 2014
Modifié(e) : Matt J le 2 Oct 2014
I doubt that avoiding loops leads to the fastest code, but the following does avoid them,
[m,n,p]=size(K);
BlockMatrix=kron(speye(p), ones(m,n));
BlockMatrix(logical(BlockMatrix))=K(:);
  2 commentaires
Mohammed
Mohammed le 2 Oct 2014
thank for posting, but where is the output matrix
Azzi Abdelmalek
Azzi Abdelmalek le 2 Oct 2014
The output is
full(BlockMatrix)

Connectez-vous pour commenter.


Matt J
Matt J le 2 Oct 2014
Modifié(e) : Matt J le 2 Oct 2014
This doesn't avoid a loop, even if it looks like it does, but it might be the fastest way.
Kcell = cellfun(@sparse, num2cell(K,[1,2]), 'uni',0 );
BlockMatrix=blkdiag(Kcell{:});

Azzi Abdelmalek
Azzi Abdelmalek le 2 Oct 2014
k(:,:,1) =[1 2;3 4]
k(:,:,2) =[5 6;7 8]
k(:,:,3) =[9 10;11 12]
out=[];
for ii=1:size(k,3)
out=blkdiag(out,k(:,:,ii))
end
  1 commentaire
Mohammed
Mohammed le 2 Oct 2014
Thank for posting your answer, but I need an answer without loops

Connectez-vous pour commenter.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by