Effacer les filtres
Effacer les filtres

Extracting non zero values from structure variable

6 vues (au cours des 30 derniers jours)
chandra Naik
chandra Naik le 26 Oct 2021
Commenté : Stephen23 le 26 Oct 2021
Suppose S is a structre variable with following zero and non-zero values , Then How do we extract only non-zero values from structure variable S.
s=100;
for i=1:s
if (sensorCover(i))
S(i).E=0.5;
S(i).xd=xf(i)
S(i).yd=yf(i)
S(i).ir=ircount(i)
S(i).cr=cf(i)
else
S(i).E=0;
S(i).xd=0;
S(i).yd=0;
S(i).ir=0;
S(i).cr=0;
end
end
  2 commentaires
KSSV
KSSV le 26 Oct 2021
Question is not clear......what is sensorCover here?
chandra Naik
chandra Naik le 26 Oct 2021
SensorCover(i)---Please assume it as any test condition. Thank you

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Sulaymon Eshkabilov
Sulaymon Eshkabilov le 26 Oct 2021
Modifié(e) : Sulaymon Eshkabilov le 26 Oct 2021
Use logical indexing to take out non-zero values from a sturcture array, e.g.:
S.m(1) =0.1; S.m(2:5)=0; S.m(6:9)=pi; S.k(1:3)=0; S.k(4:5)=-1;
S.m(S.m~=0) % Non-zero values
ans = 1×5
0.1000 3.1416 3.1416 3.1416 3.1416
S.k(S.k~=0) % Non-zero values
ans = 1×2
-1 -1
  3 commentaires
Sulaymon Eshkabilov
Sulaymon Eshkabilov le 26 Oct 2021
Most welcome!
Stephen23
Stephen23 le 26 Oct 2021
It is simpler to use NONZEROS:
S.m(1) = 0.1;
S.m(2:5) = 0;
S.m(6:9) = pi;
S.k(1:3) = 0;
S.k(4:5) = -1;
nonzeros(S.m)
ans = 5×1
0.1000 3.1416 3.1416 3.1416 3.1416
nonzeros(S.k)
ans = 2×1
-1 -1
Note that the original question showed a non-scalar structure with fields of scalar numerics, whereas the answer given above shows a scalar structure with fields of numeric vectors. These are clearly not the same thing.

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