logarithmically spaced vector in a certain range

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Azzi Abdelmalek
Azzi Abdelmalek le 3 Oct 2014
Modifié(e) : Azzi Abdelmalek le 3 Oct 2014
pas=0.1
t=log(3):pas:log(10)
out=exp(t)
%or
n=10 % number of samples
out=exp(linspace(log(3),log(10),n))

5 commentaires

Nuchto
Nuchto le 3 Oct 2014
Thanks, but isn't this an exponential curve?
What do you mean?
Nuchto
Nuchto le 3 Oct 2014
In other words, how would you then create an exponentially spaced vector? Thanks in advance.
n=10 % number of samples
out=log(linspace(exp(3),exp(10),n))
Nuchto
Nuchto le 3 Oct 2014
Thank you!

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Plus de réponses (2)

Like Marco, I would suggest using logspace. For example,
logspace(1,3,10)
creates a vector of 10 logarithmically spaced values between 10^1 and 10^3. If you instead want the bounds to be determined by a value and not the exponent, I generally use the following:
logspace(log10(3),log10(10),10)
This will create a vector of 10 logarithmically spaced values between 3 and 10.

1 commentaire

Thank Nathan, but what if I have a, b values equals to 0, 0.97, for example?
I mean, the logspaced vector is full of NaN, because of the negative logarithm...
thanks in advance

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Marco
Marco le 3 Oct 2014

1 vote

To my knwoledge you could just use the built-in command logspace.

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