stuck again with regular expression

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Max Müller
Max Müller le 5 Oct 2014
Hey Guys, I want to get the Letter before the word CAMERA out of this String:
SHOT -31045 J CAMERA
I know i need to use regexp. I have create this code
regexp(str,'(SHOT)+\b+[0-9]+\b+(.*?)+\b(CAMERA)')
But It doesnt work. Can u help me ?
SHOT and CAMERA will always be the same. Only the NUMBER and the Letter before CAMERA can be different.

Réponses (2)

Azzi Abdelmalek
Azzi Abdelmalek le 5 Oct 2014
Modifié(e) : Azzi Abdelmalek le 5 Oct 2014
str='SHOT -31045 J CAMERA'
out=regexp(str,'\S\s+(CAMERA)','match')
out=out{1}(1)
%or if there are many cases
str='SHOT -31045 J CAMERA k CAMERA'
out=regexp(str,'\S\s+(CAMERA)','match')
out=cellfun(@(x) x(1),out,'un',0)
  2 commentaires
Max Müller
Max Müller le 5 Oct 2014
Thanks and i Guess i understand what u did there. This code searches for the backspace or empty space before Camera und gives back the Word Camera + the Letter before the backspace/empty space ?
Azzi Abdelmalek
Azzi Abdelmalek le 5 Oct 2014
Or
str='SHOT -31045 J CAMERA k CAMERA'
out=regexp(str,'\S(?=\sCAMERA)','match')

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Guillaume
Guillaume le 5 Oct 2014
Modifié(e) : Guillaume le 5 Oct 2014
Where did you get that regular expression from? It doesn't mean much with matlab's regexp engine (particularly the \b does not mean blank but backspace).
If you just want a single letter before CAMERA, you can just ignore everything before and the regular expression is just a letter ([A-Za-z] or just [A-Z] if just capital letters), plus at least one blank (\s+) plus camera:
s = 'SHOT -31045 J CAMERA';
letter = regexp(s, '([A-Za-z])\s+CAMERA', 'tokens', 'once')

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