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Error using for loop to delete empty cell array elements

2 vues (au cours des 30 derniers jours)
Jaya
Jaya le 31 Oct 2021
Modifié(e) : Jaya le 15 Nov 2021
I want to completely delete the null elements of routes_log cell array. I use the following code.
temp_routes_log=routes_log
for i=1:numel(temp_routes_log)
if (isempty(temp_routes_log{i})==1)
routes_log(i)=[]
end
end
%routes_log can be like {0×0 double} {1×3 double} and I want to
% completely remove the {0×0 double} and make routes_log as just {1×3 double}
But I get error in the case when (for e.g.) 5th entry is null in temp_routes_log but as I am deleting the routes_log elements, the routes_log is no more containing 5 elements and it throws an error at
routes_log(i)=[]
I also tried storing the indices i and then deleting those routes_log elements directly but I some other error was coming. Please guide on how can I achieve the deletion.

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per isakson
per isakson le 31 Oct 2021
Modifié(e) : per isakson le 31 Oct 2021
Replace
for i=1:numel(temp_routes_log)
by
for i = numel(temp_routes_log) : -1 : 1 % loop from last to first element
OR if routes_log is large and speed becomes an issue
to_be_deleted = false(1,numel(routes_log))
for i=1:numel(temp_routes_log)
if isempty(temp_routes_log{i})
to_be_deleted(i) = true;
end
end
routes_log(to_be_deleted) = [];
Caveat: not tested
  1 commentaire
Jaya
Jaya le 31 Oct 2021
Modifié(e) : Jaya le 15 Nov 2021
For now, routes_log is not so big. So, I used the first solution. Thanks.
Update: The second method works too! I later encountered large sized routes_log & revisited this solution to try the second way.

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