'ab[c]' to this 'ab_c' ?

How can I convert this 'ab[c]' to this 'ab_c' ?

The letters a,b,c are for the specific example.

In the position of c could be any letter.

[Steven Lord]

Are you trying to change a char vector containing this literal text, or are you trying to change indexing into a variable to instead have numbered names for variables?

If the latter, can you define variables with numbered names like ab_1, ab_2, ab_3, ... ? Yes. Should you do this? Generally we recommend against it. See that page for alternatives you should use instead.

[Ioannis Vourvachakis]

I want to convert this cell array

'10fthf[c]'

'10fthf[h]'

'10fthf[m]'

'10fthf[x]' .

to this cell array

'10fthf_c'

'10fthf_h'

'10fthf_m'

'10fthf_x'

Ιn other words, I want to create a for loop, where for every element of the first cell array, it will remove the brackets ([]}and put a underscore (_) before the letter that it was previously contained in the brackets.

Answer 1

[Image Analyst]

Try this:

s = 'ab[c]'

s = 'ab[c]'

s = strrep(s, '[', '_') % Replace [ with underline.

s = 'ab_c]'

s = strrep(s, ']', '') % Replace ] with null.

s = 'ab_c'

[Ioannis Vourvachakis]

Thank you very much!!

[Image Analyst]

For a cell array, it's the same code:

s = {'ab[c]'; 'xy[z]'}
s = strrep(s, '[', '_') % Replace [ with underline.
s = strrep(s, ']', '') % Replace ] with null.

If this answers your question, maybe you can click the "Accept this answer" link, unless you want to wait for a better one.

[Ioannis Vourvachakis]

Yes, I accepted it. Thank you again.

Answer 2

[Paul]

C = { '10fthf[c]' 
  '10fthf[h]' 
  '10fthf[m]' 
  '10fthf[x]'}

C = 4×1 cell array
    {'10fthf[c]'}
    {'10fthf[h]'}
    {'10fthf[m]'}
    {'10fthf[x]'}

cellstr(extractBefore(string(C),"[") + "_" + extractBefore(extractAfter(string(C),"["),2))

ans = 4×1 cell array
    {'10fthf_c'}
    {'10fthf_h'}
    {'10fthf_m'}
    {'10fthf_x'}

[Ioannis Vourvachakis]

Thank you.