how to change variable name in for loop

I am trying to do a problem for structural analysis, i got stuck in this part trying to make a for loop give me different variables, here's the example. Thanks in advance!!
for i=1:nel
kl =[J(1,i) 0 0 -J(1,i) 0 0
0 J(3,i) J(2,i) 0 -J(3,i) J(2,i)
0 J(2,i) J(4,i) 0 -J(2,i) J(5,i)
-J(1,i) 0 0 J(1,i) 0 0
0 -J(3,i) -J(2,i) 0 J(3,i) -J(2,i)
0 J(2,i) J(5,i) 0 -J(2,i) J(4,i)]
end
I need a new "kl" each iteration, can anybody help me out, it's my first month using matlab.

1 commentaire

Jan
Jan le 11 Oct 2014
Modifié(e) : Jan le 11 Oct 2014
What is the problem with the shown code? You need a new kl in each itereation and you get a new one. So what is your question? What is the connection to the title "change varaible name"?

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 Réponse acceptée

Jan
Jan le 11 Oct 2014
A bold guess: Do you want to store the different matrices in a variable?
kl = zeros(6, 6, nel)
for i = 1:nel
kl(:,:,i) =[J(1,i) 0 0 -J(1,i) 0 0; ...
0 J(3,i) J(2,i) 0 -J(3,i) J(2,i); ...
0 J(2,i) J(4,i) 0 -J(2,i) J(5,i); ...
-J(1,i) 0 0 J(1,i) 0 0; ...
0 -J(3,i) -J(2,i) 0 J(3,i) -J(2,i); ...
0 J(2,i) J(5,i) 0 -J(2,i) J(4,i)];
end
Or in a cell array:
kl = cell(1, nel);
for i = 1:nel
kl{i} = ...

3 commentaires

Oleg Komarov
Oleg Komarov le 11 Oct 2014
Alejandro's comment moved here:
Thanks a lot, the problem was the one you boldly guessed. My only remaining question would be if there's a way of naming the matrices kl1, kl2, kl3, kl4, kln instead of kl(:,:,1) etc?
Oleg Komarov
Oleg Komarov le 11 Oct 2014
@Alejandro: absolutely avoid this programming practice. Keep the data in one place and if you need the meta info associated withe the name of the slice, then use structures or tables.
Jan
Jan le 12 Oct 2014
@Alejandro: Hiding an index in the name of a variable is a bad programming style.

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