How to improve a for

4 vues (au cours des 30 derniers jours)
Carlos
Carlos le 11 Oct 2014
Modifié(e) : Andrei Bobrov le 11 Oct 2014
Hello, i want to do this operation:
f = -[Q(:,1)'*Q(:,1); Q(:,2)'*Q(:,2); Q(:,3)'*Q(:,3); Q(:,4)'*Q(:,4); Q(:,5)'*Q(:,5); Q(:,6)'*Q(:,6); Q(:,7)'*Q(:,7); Q(:,8)'*Q(:,8); Q(:,9)'*Q(:,9); Q(:,10)'*Q(:,10)];
i have thought to do this with a for
n=10;
i=1;
while i<n+1
f(i,1)=-[Q(:,i)'*Q(:,i)]; %save in columns
i=i+1;
end
but i think there must be some way to vectorize this easily. Could you help me?
Thank you.

Réponse acceptée

Azzi Abdelmalek
Azzi Abdelmalek le 11 Oct 2014

Plus de réponses (2)

Jan
Jan le 11 Oct 2014
The vectorization is better, but here is a cleaner and more efficient loop method:
f = zeros(10, 1); % pre-allocate!!!
for k = 1:10
f(k, 1) = -(Q(:,k)' * Q(:,k));
end
  2 commentaires
Carlos
Carlos le 11 Oct 2014
Thank you so much. I think that the for loop is much better than mine before. Otherwise, how is the way to make the vectorization? Is it the answer of Azzi?
Jan
Jan le 11 Oct 2014
Yes, Carlos.

Connectez-vous pour commenter.


Andrei Bobrov
Andrei Bobrov le 11 Oct 2014
Modifié(e) : Andrei Bobrov le 11 Oct 2014
f = -dot(Q,Q).'

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by