how can i get a horzenital vector?
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X = [2 1 5 1
5 4 8 1
1 4 5 7];
if i use X1 = X(:);
the output is X1=[2
5
1
1
4
4
5
8
5
1
1
7]
but i wante the out put is X1 =[2 1 5 1 5 4 8 1 1 4 5 7];
thank you very much
0 commentaires
Réponse acceptée
Andrei Bobrov
le 14 Sep 2011
X1 = reshape(X',1,[])
2 commentaires
Jan
le 14 Sep 2011
@Fangjun: Without the transpose, you get X1 = [2,5,1,...], but Amal wants [2,1,5,...] - the data in row order.
Plus de réponses (2)
Daniel Shub
le 14 Sep 2011
If there is any chance that you matrix will have complex numbers you need to be careful with the difference between ' (ctranspose) and .' (transpose). To be clear I might go with:
X1 = transpose(X(:));
I do not know if there is a performance difference between ctranspose and transpose for real matrices.
1 commentaire
Sean de Wolski
le 14 Sep 2011
There is not. Though there was a bug with ctranspose in the original release of R2009b.
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