Notation problem: Defining an equation using parenthesis.

4 vues (au cours des 30 derniers jours)
Zena Assaad
Zena Assaad le 15 Oct 2014
Modifié(e) : Zena Assaad le 15 Oct 2014
Hi all,
I am having the following problem and I'm not sure it has a solution:
I am running the following equations within a 'for loop'.
Wf = [];
for i = 1:29
Wf = [Wf,SFC*T*(disp(i)/V1)];
W1(i+1) = W1(i)-Wf(i);
end
I have defined Wf(i) using parenthesis and I want to know if there is a way I can define W1(i+1) in the same manner.
Thanks in advance

Réponses (1)

Image Analyst
Image Analyst le 15 Oct 2014
Well sure, you did it already. You just need to make sure that Wf(1) - the first element - has been defined before you assign Wf(i+1).
However I am worried about disp(i). It seems you are using an array call disp that somehow gets assigned before the loop. disp is a built-in function so it's a very bad idea to use a variable with the same name as any built-in function.
  1 commentaire
Zena Assaad
Zena Assaad le 15 Oct 2014
Modifié(e) : Zena Assaad le 15 Oct 2014
Thanks that's a good tip I'll be sure to change it. But I need to define 'W1' not 'Wf' in parenthesis form and I'm confused how to do that when I'm working with W1(i+1)

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