Derive base 10 logarithm from base 2 log output

Hi

I am looking to calculate .

• log10 with base2log as input.i.e. log10(log2())
• log() with base2log as input i.e. log(log2())

I have only base2log function available for calculation and I don't have common log() and log10() available

Below is my code and I am looking for the right mathematical formula for conversion so that I can get equivalent log() and log10() using log2()

Thank you!!

input = 32;
b = log2(input);
constant = 2.30258509299405;   % assuming log(10)
base10  = log(b) / (constant)  % formula for conversion, I don't have log function available

base10 = 0.6990

output = log10(b)

output = 0.6990

nlog = log(input) % need conversion formula 

nlog = 3.4657

nlog = log(32)/log(2.718281828)

nlog = 3.4657

Answer 1

[Chunru]

The formula is:

For any given base b, you need to compute a constant .

[Life is Wonderful]

Thank you !! Works well