Output vector in the polyval

A quick question. How do I make this so that the value in the array is not factor out. This is my code

p=[1 0 0 0 0 -5 3 21];
x=[10 15 20];
poly_value=polyval(p,x)

poly_value = 1×3

1.0e+09 * 0.0100 0.1709 1.2800

What I mean is how can get rid of that 10^9 and instead i want the output to be what it is in the array

Answer 1

[John D'Errico]

format long g
p=[1 0 0 0 0 -5 3 21];
x=[10 15 20];
poly_value=polyval(p,x)
poly_value =
9999551                 170858316                1279998081

[Aji Bowo]

I have tried tried format long before but didnt get the same like this. What is the use of that g in the end??

[John D'Errico]

From the help for format...

format LONG      Scaled fixed point format with 15 digits for double
                 and 7 digits for single.
format LONGG     Best of fixed or floating point format with 15 
                 digits for double and 7 digits for single.

If the double precision numbers fit into 15 digits, it will try to display them without exponents. At some point, it gives up.

format long g
X = 1.2345678901234*10.^(-20:5:20)'
X =
       1.2345678901234e-20
       1.2345678901234e-15
       1.2345678901234e-10
       1.2345678901234e-05
           1.2345678901234
           123456.78901234
           12345678901.234
       1.2345678901234e+15
       1.2345678901234e+20

But even then, it is not factoring out the exponent.

format long
X = 1.2345678901234*10.^(-20:5:20)'
X =
       1.0e+20 *
       0.000000000000000
       0.000000000000000
       0.000000000000000
       0.000000000000000
       0.000000000000000
       0.000000000000001
       0.000000000123457
       0.000012345678901
       1.234567890123400

See that format long does what you do not wish to see happen.