plot stream over two spheres
Afficher commentaires plus anciens
A =[ -4.7107
0.0012
-0.0056
0.0132
-0.0253
0.0435
-0.0689
0.1031
-0.1473
0.2040
-0.2737
0.3607
-0.4647
0.5927
-0.7425
0.9265
-1.1387
1.4014
-1.7014
2.0810
-2.5114
3.0805
-3.7224
4.6475
-5.6872
7.5039
-9.5388
16.4146
-25.4535
14.3236];
B=[ -3.3794
0.0005
-0.0009
0.0006
-0.0003
0.0001
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000];
C=[ 6.8417
-0.0007
0.0007
-0.0003
0.0001
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000];
D=[ -4.7100
-0.0012
0.0058
-0.0132
0.0253
-0.0435
0.0689
-0.1032
0.1473
-0.2040
0.2737
-0.3608
0.4648
-0.5928
0.7426
-0.9266
1.1388
-1.4016
1.7016
-2.0813
2.5118
-3.0810
3.7230
-4.6482
5.6881
-7.5050
9.5403
-16.4171
25.4574
-14.3258];
E=[ -3.3789
-0.0005
0.0009
-0.0006
0.0003
-0.0001
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000];
F=[ 6.8407
0.0007
-0.0008
0.0003
-0.0001
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000];
a = 1 ; %RADIUS
L=.1;
dd=4;
kappa=1;gam=0.3;arh=1; %a2=1;u2=1;beta1=beta2=1
al=kappa.*(2+kappa)./(gam.*(1+kappa));
alpha1=real(((al.^2+arh.^2)./2+((al.^2+arh.^2).^2-(2.*kappa.*arh.^2./gam).^(1./2))./2).^(1./2));
alpha2=real(((al.^2+arh.^2)./2-((al.^2+arh.^2).^2-(2.*kappa.*arh.^2./gam).^(1./2))./2).^(1./2));
c =-a/L;
b =a/L;
m =a*100; % NUMBER OF INTERVALS
[x,y]=meshgrid([c+dd:(b-c)/m:b],[c:(b-c)/m:b]);
[I, J]=find(sqrt(x.^2+y.^2)<(a-.1));
if ~isempty(I)
x(I,J) = 0; y(I,J) = 0;
end
r=sqrt(x.^2+y.^2);
t=atan2(y,x);
r2=sqrt(r.^2+dd.^2-2.*r.*dd.*cos(t));
zet=(r.^2-r2.^2-dd.^2)./(2.*r2.*dd);
%for i1=1:length(x);
% for k1=1:length(x);
% if sqrt(x(i1,k1).^2+y(i1,k1).^2)>1./L;
% r(i1,k1)=0;r2(i1,k1)=0;
% end
% end
%end
warning off
qr1=0;
for i=2:7
Ai=A(i-1);Bi=B(i-1);Ci=C(i-1);Di=D(i-1);Ei=E(i-1);Fi=F(i-1);
qr1=qr1-(Ai.*r.^(-i-1)+r.^(-3./2).*besselk(i-1./2,r.*alpha1).*Bi+r.^(-3./2).*besselk(i-1./2,r.*alpha2).*Ci).*legendreP(i-1,cos(t))-(Di.*r2.^(-i-1)+r2.^(-3./2).*besselk(i-1./2,r2.*alpha1).*Ei+r2.^(-3./2).*besselk(i-1./2,r2.*alpha2).*Fi).*legendreP(i-1,zet);
end
hold on
[DH1,h1]=contour(x,y,qr1,3,'-k');
%axis square;
title('$(a)$ $\ell=0.1,\;\alpha=1.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%%%%%%%%%%%%%%%% $\frac{\textstyle a_1+a_2}{\textstyle h}=6.0,\;
hold on
t3 = linspace(0,2*pi,1000);
h2=0;
k2=0;
rr2=1;
x2 = rr2*cos(t3)+h2;
y2 = rr2*sin(t3)+k2;
set(plot(x2,y2,'-k'),'LineWidth',1.1);
fill(x2,y2,'w')
%axis square;
hold on
t2 = linspace(0,2*pi,1000);
h=dd;
k=0;
rr=2;
x1 = rr*cos(t2)+h;
y1 = rr*sin(t2)+k;
set(plot(x1,y1,'-k'),'LineWidth',1.1);
fill(x1,y1,'w')
%axis square;
axis off
1 commentaire
Adam Danz
le 20 Nov 2021
Shreen El-Sapa's answer moved here
I can not get the streamlines
Réponse acceptée
Cris LaPierre
le 20 Nov 2021
1 vote
qr1 is all NaNs. Assuming the countours are supposed to be your streamlines, you should check your equation. I'm not sure your for loop is doing what you intended. At the least, there is an issue with your calculation.
5 commentaires
Shreen El-Sapa
le 20 Nov 2021
Modifié(e) : Cris LaPierre
le 20 Nov 2021
edited code to make it more readable
A=[-4.7107 0.0012 -0.0056 0.0132 -0.0253 0.0435 -0.0689 0.1031 -0.1473 0.2040 -0.2737 0.3607 -0.4647 0.5927 -0.7425 0.9265 -1.1387 1.4014 -1.7014 2.0810 -2.5114 3.0805 -3.7224 4.6475 -5.6872 7.5039 -9.5388 16.4146 -25.4535 14.3236];
B=[-3.3794 0.0005 -0.0009 0.0006 -0.0003 0.0001 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0];
C=[6.8417 -0.0007 0.0007 -0.0003 0.0001 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0];
AA=[-4.7100 -0.0012 0.0058 -0.0132 0.0253 -0.0435 0.0689 -0.1032 0.1473 -0.2040 0.2737 -0.3608 0.4648 -0.5928 0.7426 -0.9266 1.1388 -1.4016 1.7016 -2.0813 2.5118 -3.0810 3.7230 -4.6482 5.6881 -7.5050 9.5403 -16.4171 25.4574 -14.3258];
BB=[-3.3789 -0.0005 0.0009 -0.0006 0.0003 -0.0001 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0];
CC=[6.8407 0.0007 -0.0008 0.0003 -0.0001 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0];
a = 1 ; %RADIUS
L=.13;
akm=1;gamma=0.3;arh=0.1;
alphaa=sqrt(((2+akm).*(akm./gamma)).^2+arh.^2);
betaa=(2.*akm.*arh.^2./gamma).^(0.25);
alpha1=sqrt((alphaa.^2+sqrt(alphaa.^4-4.*betaa.^4))./2);
alpha2=sqrt((alphaa.^2-sqrt(alphaa.^4-4.*betaa.^4))./2);
dd=5;
c =-a/L;
b =a/L;
m =a*50; % NUMBER OF INTERVALS
[x,y]=meshgrid([c+dd:(b-c)/m:b],[c:(b-c)/m:b]');
[I J]=find(sqrt(x.^2+y.^2)<(a-.1));
if ~isempty(I);
x(I,J) = 0; y(I,J) = 0;
end
r=sqrt(x.^2+y.^2);
t=atan2(y,x);
r2=sqrt(r.^2+dd.^2-2.*r.*dd.*cos(t));
zet=(r.^2-r2.^2-dd.^2)./(2.*r2.*dd);
warning on
psi1=0;
for i=2:3;
Ai=A(i-1);
Bi=B(i-1);
Ci=C(i-1);
AAi=AA(i-1);
BBi=BB(i-1);
CCi=C(i-1);
psi1=-psi1-(Ai.*r.^(-i-1)+r.^(-3./2).*besselk(i-1./2,r.*alpha1).*Bi+r.^(-3./2).*besselk(i-1./2,r.*alpha2).*Ci).*legendreP(i-1,cos(t))-(AAi.*r2.^(-i-1)+r2.^(-3./2).*besselk(i-1./2,r2.*alpha1).*BBi+r2.^(1./2).*besselk(i-1./2,r2.*alpha2).*CCi).*legendreP(i-1,zet);
end
[DH1,h1]=contour(x,y,psi1,20,'-k');
title('$(a)$ $\ell=0.1,\;\alpha=1.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
hold on
t3 = linspace(0,2*pi,1000);
h2=0;
k2=0;
rr2=1;
x2 = rr2*cos(t3)+h2;
y2 = rr2*sin(t3)+k2;
set(plot(x2,y2,'-k'),'LineWidth',1.1);
fill(x2,y2,'w')
t2 = linspace(0,2*pi,1000);
h=dd;
k=0;
rr=2;
x1 = rr*cos(t2)+h;
y1 = rr*sin(t2)+k;
set(plot(x1,y1,'-k'),'LineWidth',1.1);
fill(x1,y1,'w')
axis off
hold off
Cris LaPierre
le 20 Nov 2021
Ok. Is this what you wanted? If not, you're going to have to describe better what it is you expect.
Shreen El-Sapa
le 20 Nov 2021
Cris LaPierre
le 20 Nov 2021
Personally, I use the streamlines function to create streamlines, not contour. However, even with streamlines, you will need to calculate and input the vector field components u and v.
Shreen El-Sapa
le 20 Nov 2021
Plus de réponses (0)
Catégories
En savoir plus sur Surface and Mesh Plots dans Centre d'aide et File Exchange
le 19 Nov 2021
le 20 Nov 2021
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
