Dimension mismatch error in matlab

Hi can someone please explain me why the first one is correct and the second one generates error. I am sure it must be something easy but currently I am unable to get it

for i=1:105

x(i,:)=linspace(0,10,41);

end

>> for i=1:105

x(i,:)=linspace(0,10,48);

end

error:Subscripted assignment dimension mismatch.

Answer 1

[Michael Haderlein]

In the first loop, you either have not yet initialized x or you have initialized it as n-x-41 array. In any case, after the first loop the size of x will be [105 41]. In the second loop, you want to replace the first line of x (which has 41 entries) by an array of 48 elements. That will fail, obviously. How to solve this problem depends on what you want to do. We need a bit more information for that.