The variable g in a parfor cannot be classified..

3 vues (au cours des 30 derniers jours)
freebil
freebil le 22 Oct 2014
Modifié(e) : Edric Ellis le 23 Oct 2014
Can anyone help me with this?
parfor j=1:N
z1r=normrnd(Z1(1),Z1(2)); %Random sample from distribution of Z1
z2r=normrnd(Z2(1),Z2(2)); %Random sample from distribution of Z2
for i=1:size(T,2)
g(i)=Threshold-M(i,1)-(sqrt(lambda1)*V1(i)*z1r)-(sqrt(lambda2)*V2(i)*z2r);
if g(i)>0 %safe
IND(i,j)=0;
else %failure
IND(i,j)=1;
end
end
end

Réponses (1)

Edric Ellis
Edric Ellis le 23 Oct 2014
Modifié(e) : Edric Ellis le 23 Oct 2014
It looks like you could simply replace g(i) with g and then hoist the inner for-loop bounds calculation out of the PARFOR loop. (Inner FOR loops must have constant bounds to be able to run correctly).
I.e.
tn = size(T, 2);
parfor j = 1:N
...
for i = 1:tn
...
end
end
  2 commentaires
freebil
freebil le 23 Oct 2014
thanks but it says that IND cannot be classified then..
Edric Ellis
Edric Ellis le 23 Oct 2014
Ah, you're right, I'll update my answer.

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