How to index with a changing index
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Hi, I would like to construct a matrix L of size nxn that looks like below:
L = [a,b,c,0,0,0,0,...
     0,a,b,c,0,0,0,...
     0,0,a,b,c,0,0,...
     0,0,0,a,b,c,0,...
     ...
     0,0,0,0,...a,b,c];
I'm trying to do this without the for loop.
 i = 2:n-1;
 L(:,i-1:i+1) = repmat([a,b,c],n,1);
However, this doesn't give what I want, and I was warned by the complier that i is a non-scalar operator.
Is there a way to fix this?
Thank you very much!
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Réponses (1)
  DGM
      
      
 le 8 Déc 2021
        You can try something like this:
a = 1;
b = 2;
c = 3;
A = toeplitz([a 0 0 0 0 0 0],[a b c 0 0 0 0]);
A = A(1:end-2,:)
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