How to sort a vector based on the absolute difference of the sorted vector

Example: a= [2,3,6,12,7,18,25,0,28,5]

b= [0,2,3,5,6,7,12,18,25,28]

absolutediffofb=[2,1,2,1,1,5,6,7,3]

arrangeb=[(2,3)(5,6)(6,7)(0,2)(3,5)(25,28)(7,12)(12,18)(18,25)]

[Awais Saeed]

It is not clear what you are trying to do? How do you read 'arrangeb'? Show us what have you tried and what issues are you facing.

[Baththama Alhassan]

arrangeb are elements in b sorted based on the sorted absolute difference of b

a= [2,3,6,12,7,18,25,0,28,5]

b= [0,2,3,5,6,7,12,18,25,28]

absolutediffofb=[2,1,2,1,1,5,6,7,3]

Sortabsolutediffofb=[1,1,1,2,2,3,5,6,7]

arrangeb=(2,3)=1

(5,6)=1

(6,7)=1

(0,2)=2

(3,5)=2

(25,28)=3

(7,12)=5

(12,18)=6

(18,25)=7

Answer 1

[David Goodmanson]

Hi Awais,

a= [2,3,6,12,7,18,25,0,28,5]
b = sort(a)'            % column vector
c = [b(1:end-1) b(2:end)];
d = [diff(c,[],2) c];
e = sortrows(d)

e =
1     2     3
1     5     6
1     6     7
2     0     2
2     3     5
3    25    28
5     7    12
6    12    18
7    18    25

The ordered pairs are in columns 2 and 3. Some format like this is necessary since

[(2,3)(5,6)(6,7)(0,2)(3,5)(25,28)(7,12)(12,18)(18,25)]                            

is not part of Matlab syntax.

[Awais Saeed]

@David Goodmanson, now I understood what the question was. Thanks.

[Image Analyst]

Where is "arrangeb"? It looks like you might be missing this:

arrangeb = e(:, 2:3);

[Baththama Alhassan]

@David Goodmanson thank you