Given number of base stations and users , how can I accociate each user to the nearest base station?
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
omar th
le 14 Déc 2021
Commenté : Walter Roberson
le 19 Déc 2021
I deployed the BSs and Users randomly according to Binomial Point Process, and I assumed to connect each user to nearest BS. So, how can I accociate these users in matlab.
thanks in advance
ro=500; % radius of the layout circle
NumBSs=10; % Number of Base stations
NumUEs=50; %Number of users
center=[0 0]; % center of the circle
theta_BSs=2*pi*(rand(NumPoints,1)); % distributed random number of Base stations
g = 0.5 * ro + 0.5 * ro * rand(NumBSs,1);
PosBSs_x=center(1)+g.*cos(theta_BSs);
PosBSs_y=center(2)+g.*sin(theta_BSs);
theta1 = rand(NumUEs, 1) * 2*pi; % distributed random number of Users
r1 = ro * sqrt(rand(NumUEs, 1));
PosUE = [r1 .* cos(theta1(:)) + center(1),r1 .* sin(theta1(:)) + center(2)];
% Initial plot objects
hfig = figure('Color', 'w');
hax=axes('parent',hfig);
% Plot of deploying points
hdots=plot(PosBSs_x(:,1),PosBSs_y(:,1),'bp',PosUE(:,1),PosUE(:,2),'r.','MarkerSize', 12);
grid on
hold(hax, 'on')
axis(hax, 'equal')
% Plot the layout as circles
t = linspace(0, 2*pi);
plot(ro * cos(t) + center(1),ro * sin(t) + center(2))
0 commentaires
Réponse acceptée
Walter Roberson
le 14 Déc 2021
pdist2() the coordinates of the stations against the coordinates of the base stations to find the distance from each station to each base station. Then min() along the appropriate axes to determine the index to use.
5 commentaires
Walter Roberson
le 19 Déc 2021
For the purposes of pdist2(), you should be using rows in which each row represents one point. If some of your coefficients are represented by columns instead of rows, transpose them.
If you base stations and ground base station are represented by different spatial dimensions (for example, 2D for base stations but 3d for ground base stations), then you need to convert the coordinates to all be the longer length, perhaps by padding with zero.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Introduction to Installation and Licensing dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!